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0.5x^2+9x+20.25=8.8
We move all terms to the left:
0.5x^2+9x+20.25-(8.8)=0
We add all the numbers together, and all the variables
0.5x^2+9x+11.45=0
a = 0.5; b = 9; c = +11.45;
Δ = b2-4ac
Δ = 92-4·0.5·11.45
Δ = 58.1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{58.1}}{2*0.5}=\frac{-9-\sqrt{58.1}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{58.1}}{2*0.5}=\frac{-9+\sqrt{58.1}}{1} $
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